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Solids in liquids |
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Salt dissolved in water |
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Liquid in a liquid |
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Alcohol dissolved in water |
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Gas in a liquid |
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Carbonated water |
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Gas in a Gas |
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Air |
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Gas in a solid (Hydrogen in Platinum) |
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Liquid in a solid (Amalgam) |
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Solid in a solid (Alloy) |
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Heat of Solution-Energy exchange that takes
place when a solution is formed |
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Endothermic Heat of solution- Energy is absorbed
as a solution is formed |
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Exothermic Heat of Solution- Energy released
when a solution is formed |
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Hydrate-Compound that has water molecules locked
into the crystal structure (water of hydration) |
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Test for Identifying a Hydrate |
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Releases the water of hydration upon heating |
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Anhydrous residues revert back to the original
hydrate in the presence of water |
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Anhydrous residue will dissolve in excess water
and produce a solution with the same color as the original hydrate solid |
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Concentration-The amount of solute in a given
amount of solvent |
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Types of Concentration |
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Percent |
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Mass/mass (m / m) |
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Mass / volume (m / v) |
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Volume / volume (v / v) |
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Mole Fraction (X) |
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Molarity (M) |
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Molality (m) |
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Mass Percent (m / m) |
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% m/m = (mass of solute / mass solution) x 100 |
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Mass / Volume Percent |
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% m/v = (mass of solute / vol of solution) x 100 |
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Volume / Volume Percent |
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% v/v = (vol of solute / vol of solution) x 100 |
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Parts Per Million (ppm) |
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ppm = (mass of solute / mass of solution) x 10 6 |
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Problem |
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Mole Fraction (X) |
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X 1 = mols of component 1 / total
mols of all components |
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X 1 + X 2 + X 3
+ ….X n = 1 |
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Molarity (M) |
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M = mols of solute / vol of solution in liters |
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M = millimols of solute / vol of solution in ml |
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Problems |
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Molality(m) |
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m = mols of solute / kg of solvent |
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Given the mass Percent and density of solution
determine: |
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Mole fraction |
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Molarity |
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Molality |
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Solubility- amount of solute required to reach
saturation with a given amount of solvent |
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Unsaturated solution-solution below the
solubility limit of a solution |
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Saturated solution- solution at the solubility
limit of a solution (solute and solvent in equilibrium with solution) |
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Supersaturated solution- solution above the
solubility limit of the solution (meta-stable state) |
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Solute-solvent interaction |
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Pressure |
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Temperature |
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Hydrophilic groups of atoms attract water |
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Hydrophobic groups of atoms repel water |
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Alcohol solubility |
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Relative solubility |
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1-4 carbon alcohols infinitely solubility in
water |
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5-6 carbon alcohols are moderately soluble in
water |
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7 carbon alcohols and up are insoluble in water |
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In general, the greater the molecular forces
between solute and solvent molecules the greater the solubility |
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For molecular substances, Hydrogen Bonding
interactions are most influential |
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Increasing the pressure of a gas over its
solution increases the concentration of solution |
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Diver’s Bends-collection of Nitrogen gas at
joints due to release of gas as diver ascends too fast |
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Henry’s Law-The concentration of a gas in a
solvent is directly proportional to the pressure of that gas above the
solution |
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Cg = kPg where k = Henry’s Constant for
solvent Cg is concentration of
gas and Pg is the Pressure of gas above the solution |
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Problem |
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Follows Equilibrium Laws since solubility is
under saturated conditions where a dynamic equilibrium exists |
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For endothermic Heats of solution: |
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Increasing Temperature increases solubility |
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For exothermic Heats of solution: |
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Increasing the Temperature decreases the
solubility |
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Colligative Property-property that depends upon
the number of particles in solution. |
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Kinds of colligative properties: |
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Vapor Pressure Lowering |
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Boiling Point Elevation |
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Freezing Point Depression |
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Osmotic Pressure Elevation |
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Electrolyte-substance whose solution conducts an
electrical current |
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Requires the releasing of ions |
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Greater the ion production in the solution the
greater the conduction of current through the solution. |
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HCl
+ H2O --à H3O + +
Cl – complete ionization= strong electrolyte |
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HC2H3O2 +
H2O = H3O + +
C2H3O2 - Partial Ionization = weak electrolyte |
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NaCl
+ H2O -à Na +(aq) +
Cl –(aq) Complete
Dissociation = strong electrolyte |
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Non-Electrolyte- substance whose solution does
not conduct an electrical current. |
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No ions produced during solution formation |
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All particles in solution are molecular (no
ions) |
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i = number of mols of particles after solution
formation / number of mols of particles before solution formation takes
place |
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C6H12O6(s) +
H2O --à C6H12O6(aq) |
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i = 1 / 1 = 1 |
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Ca3(PO4)2 +
H2O ---à3Ca +2 (aq) +
2PO4 –3 (aq) |
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i = 5 / 1 = 5 |
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For the same concentration of C6H12O6
and Ca3(PO4)2 the effect upon the
colligative property will be 5 times greater in the Ca3(PO4)2
solution |
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In more concentrated solutions two or more ions
act as a single particle thus the number of particles in solution is less
than I factor would predict |
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The more concentrated solutions would have
colligative properties deviate from Ideal Solution Behavior |
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In Ideal Solution assume that interionic
particle attraction would approach zero. This would be more true if the
concentration were decreased |
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Vapor Pressure of a solvent decreases as the
concentration of solute increases(macroscopic View) |
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Molecular View Explaination |
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As more solute particles are added (increased
concentration), they have a better chance of replacing surface solvent
particles thus decreasing the chance for solvent particles to escape into
vapor state. An assumption is that
the solute particles are relatively non-volatile and would not vaporize. |
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The vapor pressure of the solvent in a solution
will decrease with decreasing solvent concentration (or increasing solute
concentration) |
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P1 = iX1P10 where P1 is Vapor press of
solvent in solution ; X1 is mole fraction of solvent and P10
is the vapor press of pure solvent; i is the I factor of the solution |
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Problem |
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Boiling Points are always elevated with increase
in solute concentration |
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Molecular view |
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As the solute concentration is increased vapor
pressure is decreased (Raoult’s Law).
The temperature of boiling would have to be greater to compensate
for this lower vapor pressure |
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Tb – Tb0 = i kb
m |
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where Tb is BP of solvent in
solution; Tb0 is B.P. of pure solvent; kb is boiling
point elevation constant for solvent; m is the molal concentration; i is
the i-factor for solution. |
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Problem |
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Freezing Point decreases with increasing solute
concentration. |
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Molecular View |
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As solute particles increase they are more
likely to take the place of the solvent particles in the crystal lattice
thus weakening the crystal structure and making the crystal structure more
likely to collapse at a lower temperature (lower kinetic energy) |
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Tf 0 – Tf = i kf
m where Tf 0
is the Freezing Point of pure solvent; Tf is the Freezing Point
of the solvent in the solution; kf is the Freezing Point Depression
Constant of the solvent; m is the molal concentration; i is the i-factor of
the solution. |
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Problem |
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Osmotic Pressure-Pressure difference between a
solution and a pure solvent |
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Osmotic Pressure increases with increasing
solute concentration (macro view) |
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Molecular View |
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As the number of solute particles increase there
are fewer solvent molecules that can pass from one side of a semi-permeable
membrane to the less concentrated side but more water molecules will be
able to pass to the more concentrated side |
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People on an elevator analogy |
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Pi = i M R T
where Pi is the Osmotic pressure; M is the Molarity concentration; R
is the universal Gas Law Constant; T is the Kelvin Temperature; i is the
i-factor for the solution |
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Problem |
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Isotonic solution-solutions of the same
concentrationas solution on the other side of membrane |
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Hypotonic solutions-solutions of smaller
concentration compared to concentration of solution on the other side of
membrane |
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Hypertonic solution-solution of a higher
concentration than solution on the other side of membrane |
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When cells are : |
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Isotonic
the cells have just as much water entering as is leaving hence no
change |
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Hypotonic the cells have more water leaving the
cell than can enter hence cells shrink in size because of water
loss(crenation) |
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Hypertonic the cells have more water entering
the cell than exits and the cells swell(hemolysis) |
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In general,osmosis always occurs from the less
concentrated side to the more concentrated side(increased entropy) |
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Using Boiling Point Elevation or Freezing Point
Depression Data |
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MM = I k (mass of solute) / kg of solvent (
Delta T) |
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Problem |
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Using Osmotic Pressure Data |
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MM = i (mass of solute)R T / Osmotic
Pressure(Volume of solution in liters) |
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Problem |
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