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Chemical Kinetics-Study of reaction rates of
Chemical and Physical Processes |
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Reaction Rate-Change in the concentration of a
reactant or product per unit time |
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Types of Reaction Rates |
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1. Instantaneous Rate |
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2. Average Rate |
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For reaction:
H2O2 -à H2O + ½ O2 |
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Product Formation |
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R avg = D[O2] / Dt = [O2]final
– [O2]initial / tf-ti |
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Reactant Disappearence |
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R avg = - D[H2O2] / Dt = - [H2O2]final – [H2O2]initial
/ tf-ti |
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Problem |
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Solute-Solvent Interactions |
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Concentration of Reactants (in rate determining
step) |
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Temperature Change |
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Effect of a Catalyst |
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Gaseous state produces the largest Reaction
rates compared to same reactants in liquid state |
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Solid State of reactants produce the slowest
rates when compared to liquid or gaseous states |
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Relative Rates |
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Gaseous > solution> liquid> solid |
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Reaction Rates increase with increasing
entropy(degrees of freedom) of reactants |
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For a reaction process: aA
+ bB --à cC |
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R~(Conc A) m |
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R~(Conc B) n |
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Therefore:
R ~ (Conc A) m (Conc B) n |
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R = k[A]m [B]n where k = rate constant and m and n are
rate orders |
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Combined rate order = m + n |
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First order Kinetics in respect to a component |
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Doubling the concentration doubles the rate |
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R1 = k[A] if [A] becomes [2A] then R2 = k[2A] = 2k[A] |
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R2 = 2R1 |
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Second Order kinetics |
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Doubling the concentration will quadruple the
rate |
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R1 = k[A]2 if [A] becomes [2A] then R2 =
k[2A]2 = 4k[A]2 |
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R2 = 4R1 |
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Third Order kinetics |
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Doubling the concentration will raise the rate
by a factor of 8 |
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Proportionality Constant of the Kinetic Rate Law
Relationship |
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Determine Rate orders of the expression from lab
data collected |
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Determine Rate constant, k using lab data
collected |
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Plug into the general rate Expression the rate
orders and rate constant to give most definitive expression |
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Log vs time is linear follows slope intercept
formula |
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Y = mx + b |
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Log [A]t / log [A]0 = - kt
/ 2.303 or ln [A]t / ln [A]0
= - kt where [A]t =
final conc; [A]0
= initial conc; k = rate constant; t= time of reaction |
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Derivation(optional) |
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Problem |
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Half Life-The time it takes for half of the
remaining reactant to undergo its change to product |
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[A]t = [A]0 / 2 |
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t ½ = .693 / k |
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Derivation(optional) |
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Problem |
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