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Part 1-Energy Exchanges and Calorimetry |
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Kinetic Energy-Energy of motion(Thermal,
Electrical. Magnetic,etc) |
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KE = ½(mass)(velocity)2 = ½ mv2 |
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Examples-moving object; molecular motion;
electron motion |
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Example Problem |
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Potential Energy-Energy of Position |
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PE = (mass)(acceleration due to
gravity)(distance from reference point)= mgh |
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Examples- coiled spring; energy locked within
molecules |
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Total Energy = KE + PE |
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KE--à PE |
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Reactions that absorb kinetic energy to produce
new product molecules |
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PE -à KE |
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Chemical Reaction that produces energy from
product formation |
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Calorie(cal)- amount of energy required to raise
1 gram of water by 1 degree Celsius |
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Joule(j) |
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1 calorie = 4.18 Joules |
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Kcalorie (Kcal) |
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1000 calories = 1 Kcal = 4180 j |
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Kilojoule (Kj) |
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1 Kj = 1000 j |
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Endothermic- Energy enters the System from the
Environment(ie: absorbed by System) |
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Energy taken from environment lowering its
temperature |
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Temperature lowering indicative of a reaction
system that is endothermic |
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Exothermic- Energy is given off by or exits the
System to the environment |
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Energy is added to the environment increasing
its temperature |
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Temperature increasing indicative of a reaction
system that is exothermic. |
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Heats of Reaction ( DH )- The energy exchanged by a
reaction system and its environment |
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Types of Heats of Reaction ( D H = Hf – Hi) |
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Heat of solution |
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Heat of sublimation |
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Heat of Combustion |
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Heat of Compound Formation |
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If D H > 0 (ie:positive) Then reaction is endothermic |
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Product Energy State (enthalpy) > reactant
energy state |
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If D H <0 (ie:negative)
Then reaction is exothermic |
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Product energy state < Reactant energy state |
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Thermochemical Equation- balanced equation with
an energy term included |
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A
+ B --à C +
D + energy |
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Exothermic reaction with D H < 0 |
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A
+ B +
energy --à C + D |
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Endothermic reaction with D H > 0 |
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If the equation is multiplied by a common factor
then the D
H is also multiplied by the same factor |
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If equation is reversed then D H changes sign |
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2H2
+ O2 -à 2H2O DH = -483.7 Kj |
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2 mols H2 = -483.7 Kj |
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1 mol O2 = -483.7 Kj |
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2 mols H2O = -483.7 Kj |
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Thermo chemical Stoichiometry Problems |
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1 2 |
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Grams of given -à mols of given-à Kj of requested |
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Grams of given
x 1 mol given / molecular
mass in grams = mols of given |
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Mols of given
X D H / 1 mol given = Kj energy
requested |
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Example |
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Heat Flow = q = (mass of system) (specific heat
of system) (final temp – Initial Temp) |
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Q = mcD t = mc(tf – ti) |
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Example |
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